设 f(x) = ln(1+ax)/sin2x (x>0) ,f(x) = 1 (x = 0),f(x) = (e^bx - 1)/x (x

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设 f(x) = ln(1+ax)/sin2x (x>0) ,f(x) = 1 (x = 0),f(x) = (e^bx - 1)/x (x

设 f(x) = ln(1+ax)/sin2x (x>0) ,f(x) = 1 (x = 0),f(x) = (e^bx - 1)/x (x
设 f(x) = ln(1+ax)/sin2x (x>0) ,f(x) = 1 (x = 0),f(x) = (e^bx - 1)/x (x

设 f(x) = ln(1+ax)/sin2x (x>0) ,f(x) = 1 (x = 0),f(x) = (e^bx - 1)/x (x
a=2 b=1
在X=0点连续,左极限和右极限都是1
在求左右极限的时候可以用等价无穷小 也可以用罗比达法则

用罗毕达法则,分子分母同时求导即可
a=2
b=1