若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 15:07:15
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z

若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z=0
zx/﹙z+2x﹚=3③

若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z
对等式①,②,③取倒数可得
2/x + 1/y = 1 (1)
2/y + 1/z = 1/2 (2)
2/z + 1/x = 1/3 (3)
(1)* 4 - (2)*2 + (3)可得9/x = 10/3,x=27/10,
把x=27/10带入(1)可得y= 27/7,
把x=27/10带入(3)可得z= -54.
所以10x+7y+z=0,答案为D.

你是不是少东西了 那个③等于多少啊