先化简,在求值:(1+x-1/1)÷x²-1/x·x+1/2x,其中x=2√3-2

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先化简,在求值:(1+x-1/1)÷x²-1/x·x+1/2x,其中x=2√3-2

先化简,在求值:(1+x-1/1)÷x²-1/x·x+1/2x,其中x=2√3-2
先化简,在求值:(1+x-1/1)÷x²-1/x·x+1/2x,其中x=2√3-2

先化简,在求值:(1+x-1/1)÷x²-1/x·x+1/2x,其中x=2√3-2
分式不是这样表示的,(x-1)分之1,应该表示为:1/(x-1)
你的题目应该是:
[1+1/(x-1)]÷x/(x²-1) *2x/(x+1)
=[(x-1)/(x-1)+1/(x-1)]÷x/[(x+1)(x-1)] *2x/(x+1)
=x/(x-1)÷x/[(x+1)(x-1)] *2x/(x+1)
=x/(x-1) *(x+1)(x-1)/x *2x/(x+1)
=(x+1)*2x/(x+1)
=2x
=4√3-4

=[1+1/(x-1)] ×(x+1)(x-1)/x×2x/(x+1) 1/(x-1)是(x-1)分之1
=x/(x-1)×(x+1)(x-1)/x×2x/(x+1)
=2x
=4√3-4

[﹙x﹢﹚/﹙x﹣x﹚﹣﹙x-﹚/﹙x-x﹣﹚]÷﹙-x﹚/x=[﹙x﹢﹚/x﹙x﹣﹚﹣﹙x-﹚/﹙x-)]÷﹙-x﹚/x=[﹙x﹢﹚﹙x﹣﹚/x原式=-/ 恩,对 我看错了 原式得 X+/X(x-)-(x-)/(X-)*X/-X X--X+X/X(X-)*X/-X-/(X-)当x=-时 原式=-/(--)