0=60%-15%- [(1+x)/x]×5%×100%-100/(1000×x)

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/30 01:22:27
0=60%-15%- [(1+x)/x]×5%×100%-100/(1000×x)

0=60%-15%- [(1+x)/x]×5%×100%-100/(1000×x)
0=60%-15%- [(1+x)/x]×5%×100%-100/(1000×x)

0=60%-15%- [(1+x)/x]×5%×100%-100/(1000×x)
0=60%-15%- [(1+x)/x]×5%×100%-100/(1000×x)
0=45%-[(1+x)/x]×5%-100/(1000×x)
两边同时乘以100x,得
0=45x-5(1+x)-10
40x=15
x=3/8

若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂) (x)-2x·x-x-2x+1=0求x的值, 设f(x)={x^sin(1/x),x>0 a+e^x,x 因式分解法解下列方程 1、用因式分解法解下列方程:(1)3y^2-5y=0 (2)4x^2=12x (3)x^2+9=-6x (4)9x^2=(x-x^3-3x^2-13x+15 =x^3-3x^2+2x-15x+15 =x(x^2-3x+2)-15(x-1) =x(x-2)(x-1)-15(x-1) =(x-1)[x(x-2)-15] =(x-1)[x^2-2x-15] =(x-1)(x-5)(x+ matlab解数值分析题p=(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)解为1,2,3……,20取多个非常小的数用软件工具求解方程p(x)+n*x^19=0,并 先化简再求值(x-1/x-x-2/x+1)/(2x²-x/x²+2x+1)且x²-x-1 =0 (X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0 0=60%-15%- [(1+x)/x]×5%×100%-100/(1000×x) (X-1)(X-2)(X+2)(X+3)=60(X-1)(X-2)(X-3)(X-4)+1=0(X-5)/(X-6)+(X-8)/(X-9)=(X-7)/(X-8)+(X-6)/(X-7) x*x*x*x+2008x*x+2007x+2008(提示:x*x*x-1=(x-1)*(x*x+x+1)) 1.3x的平方+5(2x+1) 2.x的平方-2x-15=0 3.7x(5x+2)=6(5x+2) f(x)=(x+1)ln(x+1)+m(x^2+2x) x>=0时,f(x) (x-2)(x²-6x-9)-x(x²-2x-15),其中x=1/3 已知x²-2010=0求x(x+1)²-x(x²+x)-x-2011的值 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X f(x)=x/(1+x) x>=0 f1(X)=f(X) fn(X)=fn-1[fn-1(x)]求fn(x)证明:f1(X)+2f2(X)+3f3(x)+……+nfn(X) (1-3/x+2)÷x-1/x²+2x-x/x+1,其中x满足x²-x-1=0 已知f(x)= -x^2-2x g(x)= 分段函数 x+1/4x(x>0),x+1(x