作业帮[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/28 05:39:47
![[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)](/uploads/image/z/2701119-39-9.jpg?t=%5Blog2+%28125%29+%2Blog4%2825%29%2Blog8%285%29%5D%5Blog125%288%29%2Blog25%284%29%2Blog5%282%29)
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
=[3*log2(5)+log2(5)+1/3*log(5)]*[log5(2)+log5(2)+log5(2)]
=[7/3*log2(5)]*[3log5(2)]
=7*log2(5)*log5(2)
=7
log2 20-log4 25
log2 20-log4 25的答案是
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)][log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
log4(log2^x)=log2(log4^x)求log2^x
(log2 5+log4 125)log3 2/ log根号3 5
log4^25-2log4^10+log2^9×log3^根号5×log5^2
log2^x=log4^9
2log2为什么等于log4
log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X
log4 243 - log8 729=?log4 12 - log2 6=?
高中数学对数计算求值（log2 125+log4 25+log8 5）*（log125 8+log25 4+log5 2）要用简便运算啊.
关于对数运算（lg5）^2+lg2·lg50=?(log2 125+log4 25+log8 5)·(log125 8+log25 4+log5 2)=?
(log2(5）+log4（125））×log3（2）/log根号3（5）
(log2^5+log4^125)(log3^2)/(log(根号3)^5 要具体的过程,
(log2(5)+log4(125))(log3(2)/log√3(5))怎么解?
3^log9(25)+16^log4(2)-(根号7)^log7(9)+(-1)^log2(1)