分式的运算、我给100!6x/x^2-x - 2+(1-1/x+1) ÷ (1+1/x-1) + 1/x-2x^3/x^n-1 - x^2n/x^n+1 - 1/x^n-1 + 1/x^n+1(x^2-1/y^2)÷(x+1/y)(a+b/a-b - a^3+b^3/a^3-b^3)(a+b/a-b)1/x+1 - x+3/x^2-1 ×x^2+2x+1/x^2+4x+31/1-x + 1/1+x + 2/1+x^2 + 4/1+x^2第一个

分式的运算、我给100!6x/x^2-x - 2+(1-1/x+1) ÷ (1+1/x-1) + 1/x-2x^3/x^n-1 - x^2n/x^n+1 - 1/x^n-1 + 1/x^n+1(x^2-1/y^2)÷(x+1/y)(a+b/a-b - a^3+b^3/a^3-b^3)(a+b/a-b)1/x+1 - x+3/x^2-1 ×x^2+2x+1/x^2+4x+31/1-x + 1/1+x + 2/1+x^2 + 4/1+x^2第一个
分式的运算、我给100!
6x/x^2-x - 2+(1-1/x+1) ÷ (1+1/x-1) + 1/x-2
x^3/x^n-1 - x^2n/x^n+1 - 1/x^n-1 + 1/x^n+1
(x^2-1/y^2)÷(x+1/y)
(a+b/a-b - a^3+b^3/a^3-b^3)(a+b/a-b)
1/x+1 - x+3/x^2-1 ×x^2+2x+1/x^2+4x+3
1/1-x + 1/1+x + 2/1+x^2 + 4/1+x^2
第一个：6x/x^2-x-2 + (1-1/x+1) ÷ (1+1/x-1) + 1/x-2
倒数第二个：1/x+1 - x+3/x^2-1 × x^2+2x+1/x^2+4x+3
分子

分式的运算、我给100!6x/x^2-x - 2+(1-1/x+1) ÷ (1+1/x-1) + 1/x-2x^3/x^n-1 - x^2n/x^n+1 - 1/x^n-1 + 1/x^n+1(x^2-1/y^2)÷(x+1/y)(a+b/a-b - a^3+b^3/a^3-b^3)(a+b/a-b)1/x+1 - x+3/x^2-1 ×x^2+2x+1/x^2+4x+31/1-x + 1/1+x + 2/1+x^2 + 4/1+x^2第一个
r所有的题目表达不准确,甚至是错误的,让人无法正确理解.大中小括号一定正确使用.我的理解是:
1.
6x/(x^2-x-2)+[1-1/(x+1)]÷[1+1/(x-1)]+1/(x-2)
=6x/[(x-2)(x+1)]+[(x+1-1)/(x+1)]/[(x-1+1)/(x-1)]+1/(x-2)
=6x/[(x-2)(x+1)]+[x/(x+1)]/[x/(x-1)]+1/(x-2)
=6x/[(x-2)(x+1)]+(x-1)/(x+1)+1/(x-2)
=6x/[(x-2)(x+1)]+[(x-1)(x-2)]/[(x+1)(x-2)]+(x+1)/[(x+1)(x-2)]
=[6x+(x-1)(x-2)+(x+1)]/[(x+1)(x-2)]
=(x^2+4x+3)/[(x+1)(x-2)]
=(x+3)/(x-2)
2.
x^3/(x^n-1)-x^2n/(x^n+1)-1/(x^n-1)+1/(x^n+1)
=[x^3/(x^n-1)-1/(x^n-1)]+[1/(x^n+1)-x^2n/(x^n+1)]
=[(x^3-1)/(x^n-1)]-[(x^2n-1)/(x^n+1)]
=[(x-1)(x^2+x+1)/(x-1)(x+1)]-[(x^n+1)(x^n-1)/(x^n+1)]
=(x^2+x+1)/(x+1)-(x^n-1)
=(x^2+2x+1-x)/(x+1)-(x^n-1)
=(x+1)-x/(x+1)-(x^n-1)
=(-x^n+x+2)-x/(x+1)
3.
[(x^2-1)/y^2]÷[(x+1)/y]
=[(x+1)(x-1)/y^2]/[(x+1)/y]
=(x-1)/y
或者是:
(x^2-1/y^2)÷(x+1/y)
=[(x^2*y^2-1)/y^2]÷[(xy+1)/y]
=[(xy+1)(xy-1)/y^2]÷[(xy+1)/y]
=(xy-1)/y
4.
[(a+b)/(a-b)-(a^3+b^3)/(a^3-b^3)][(a+b)/(a-b)]
=[(a+b)(a^2+ab+b^2)/(a^3-b^3)-(a+b)(a^2-ab+b^2)/(a^3-b^3)][(a+b)/(a-b)]
={[(a+b)(a^2+ab+b^2)-(a+b)(a^2-ab+b^2)]/(a^3-b^3)}[(a+b)/(a-b)]
=[(a+b)(4ab)/(a^3-b^3)][(a+b)/(a-b)]
=4ab*(a+b)^2/[(a-b)*(a^3-b^3)]
(题目好象有点问题,最后一个因数应该是除而不是乘.即:
[(a+b)/(a-b)-(a^3+b^3)/(a^3-b^3)]/[(a+b)/(a-b)]
5.
1/(x+1)-(x+3)/(x^2-1)×(x^2+2x+1)/(x^2+4x+3)
=1/(x+1)-(x+3)/(x+1)(x-1)×[(x+1)^2/(x+1)(x+3)]
=1/(x+1)-1/(x-1)
=(x-1)/(x+1)(x-1)-(x+1)/(x+1)(x-1)
=-2/(x+1)(x-1)
6.
1/(1-x)+1/(1+x)+2/(1+x^2)+4/(1+x^2)
=(1+x)/[(1+x)(1-x)]+(1-x)/[(1+x)(1-x)]+6/(1+x^2)
=2/[(1-x^2)]+6/(1+x^2)
=2(1+x^2)/[(1-x^2)(1+x^2)]+6(1-x^2)/(1+x^2)(1-x^2)
=[2(1+x^2)+6(1-x^2)]/(1+x^2)(1-x^2)
=4(2-x^2)/(1-x^4)

2：x^(3+n)+x^3-x^3n+x^2n-2/(x^2n-1)
3:(xy-1)/y另：如（x^2-1）、(x+1)是分子则答案：（x-1）/y
4:2ab(a+b)^2/(a-b)(a^3-b^3)
6:8-4x^2/1-x^4
1：x+3/x-2
5:(3x-4)/x^2+4x+3-(x^3+3x^2)/x^2-1=（x-4-x^4-6x^3-6x^2）/x^3-3x^2-x-3

我拿了两分就充充离开了,100我不要！