log(2x – 3)(x2－3)＞0求解

解log(2x – 3)(x2－3)＞0 (2x-3)是底数. log(2x – 3)(x2－3)＞0求解 求y=log½(3+2x－x2)的值域 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 log(x+3)(x2+3x)=2,求实数x的值 设函数f (x)＝x2－x＋b拜托各位了 3Q设函数f (x)＝x2－x＋b,已知log 2f (a)＝2,且f (log 2a)＝b (a>0且a≠1),(1) 求a,b的值；(2) 试在f (log 2x)>f (1)且log 2f (x) log(2)(x-1)=log(2)(x2+2x-3)求解!要步骤!谢谢 求log(x+3) 2 log(3x)= log 4 +log(6-x)怎么求...急 求函数y=log(x-1)（-X2+2X+3）的定义域.括号里那是x的平方 已知x2－4x+1=0,求x2／(x2)2－3x2+1 log(2)(x)log(2)(4x)-3log(2)(x)-12=0 (log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0 (1)已知log（a）x=2,log(b)x=4,求log(abc)x(2)如果方程lg^2x+(lg2+lg3)lgx+lg2*lg3=0的两个根为x1,X2,求X1*x2 已知log(2){log(3)[log(4)(x)]}=5^0,则x=? log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, log数学题,求救!高中水平就可以!log(x+8)-log2=log(3x+2)求x. （高一）若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{log(√2)[(√x)/2]}的最大值和最小若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{log(√2)[(√x)/2]}的最大值和最小值,并求此时x的值.rt