1/1*2*3+1/2*3*4+…+1/98*99*100

(1)|1+(-1/2)|+|1/2+(-1/3)|+|1/3+(-1/4)+…+|1/9+(-1/10)|=?(2)1+（-2）+3+（-4）+…+99+（-100）=?请不要只是写出答案,请简单说明一下解题的思路,小妹在此谢谢了!(1)

|1/3+(-1/2)|+|1/4+(-1/3)|+|1/5+(-1/4)|+……+|1/2010+(-1/2009)||1/3+(-1/2)|+|1/4+(-1/3)|+|1/5+(-1/4)|+……+|1/2010+(-1/2009)|

1/(1-1/2)/(1-1/3)/(1-1/4)/……/(1-1/2012)1/(1-1/2)/(1-1/3)/(1-1/4)/……/(1-1/2012)1/(1-1/2)/(1-1/3)/(1-1/4)/……/(1-1/2012)1/(

2(3+1)(3^2+1)(3^4+1)……（3^32+1)+12(3+1)(3^2+1)(3^4+1)……（3^32+1)+12(3+1)(3^2+1)(3^4+1)……（3^32+1)+12(3+1)(3^2+1)(3^4+1).(3^

(1-1/2×1/2)×(1-1/3×1/3)×(1-1/4×1/4)×…×(1-1/2005×1/2005)(1-1/2×1/2)×(1-1/3×1/3)×(1-1/4×1/4)×…×(1-1/2005×1/2005)(1-1/2×1/2

|1/2|+|1/3-1/2|+|1/4-1/3|+|1/5-1/4|+……+|1/2014-1/2013|+|1/2015-1/2014|等于多少|1/2|+|1/3-1/2|+|1/4-1/3|+|1/5-1/4|+……+|1/2014

(-1×1/2)+(-1/2×1/3)+(1/3×1/4)+…+(-1/2011×1/2012)+(-1/2012×1/2013)=?(-1×1/2)+(-1/2×1/3)+(1/3×1/4)+…+(-1/2011×1/2012)+(-1/

(-1×1/2)+(-1/2×1/3)+(-1/3×1/4)+…+(-1/2012×1/2013)求大神指导~(-1×1/2)+(-1/2×1/3)+(-1/3×1/4)+…+(-1/2012×1/2013)求大神指导~(-1×1/2)+(

(-1*1/2)+(-1/2*1/3)+(1/-3*1/4)+…+(-1/2012*1/2013)求过程(-1*1/2)+(-1/2*1/3)+(1/-3*1/4)+…+(-1/2012*1/2013)求过程(-1*1/2)+(-1/2*1

[1+(-1/2)]+[1/2+(-1/3)]+[1/3+(-1/4)]+…+[1/1999+(-1/2000)]=?等于多少啊?A.2000/1999B.1999/2000C.1/2000D.1/1999[1+(-1/2)]+[1/2+(

|1/2-1|+|1/3-1/2|+|1/4+1/3|+…+|1/30-1/29||1/2-1|+|1/3-1/2|+|1/4+1/3|+…+|1/30-1/29||1/2-1|+|1/3-1/2|+|1/4+1/3|+…+|1/30-1/

计算|1-1/2|+|1/3-1/2|+|1/4-1/3|+…+|1/1000-1/999|.如题.一定要有过程啊.计算|1-1/2|+|1/3-1/2|+|1/4-1/3|+…+|1/1000-1/999|.如题.一定要有过程啊.计算|1

1/1+2+1/1+2+3+1/1+2+3+4+…+1/1+2+3+…+501/1+2+1/1+2+3+1/1+2+3+4+…+1/1+2+3+…+501/1+2+1/1+2+3+1/1+2+3+4+…+1/1+2+3+…+501/1+2+

求证：1/2^3+1/3^3+1/4^3+……+1/(n+1)^3求证：1/2^3+1/3^3+1/4^3+……+1/(n+1)^3求证：1/2^3+1/3^3+1/4^3+……+1/(n+1)^31/n^3

求证：1/2^3+1/3^3+1/4^3+……+1/(n+1)^3求证：1/2^3+1/3^3+1/4^3+……+1/(n+1)^3求证：1/2^3+1/3^3+1/4^3+……+1/(n+1)^31/2^3+{1/3^3+1/4^3+……

求和:1/1×2+1/2×3+1/3×4+……+1/n(n+1)求和:1/1×2+1/2×3+1/3×4+……+1/n(n+1)求和:1/1×2+1/2×3+1/3×4+……+1/n(n+1)1/1×2+1/2×3+1/3×4+……+1/n

计算：(1+1/2)(1+1/3)(1+1/4)…(1+1/2010)(1/2-1)(1/3-1)(1/4-1)…(1/2011-1).注：“/"为分数线计算：(1+1/2)(1+1/3)(1+1/4)…(1+1/2010)(1/2-1)(

1、巧算：(1-1/2^2)×(1-1/3^2)×(1-1/4^2)×……×(1-1/2008^2)2、已知2009-a的绝对值与a-2010的算术平方根的和为a,求a-2009^2+15的算术平方根.1、巧算：(1-1/2^2)×(1-1

(1-1/2)×(1-1/3)×(1-1/4)……×（1-1/2008）计算方法(1-1/2)×(1-1/3)×(1-1/4)……×（1-1/2008）计算方法(1-1/2)×(1-1/3)×(1-1/4)……×（1-1/2008）计算方法

200×(1-1/2)×(1-1/3)×(1-1/4)×……×(1-1/100)=?200×(1-1/2)×(1-1/3)×(1-1/4)×……×(1-1/100)=?200×(1-1/2)×(1-1/3)×(1-1/4)×……×(1-1/