作业帮函数y=tan[(1+x/(a+b)]的周期为π,y=sin((a-b)x+π/4)的周期为3π,求a,b的值.答案a=5/6,b=1/6 a=1/6,b=5/6 a=-1/6,b=-5/6 a=-5/6,b=-1/6
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![函数y=tan[(1+x/(a+b)]的周期为π,y=sin((a-b)x+π/4)的周期为3π,求a,b的值.答案a=5/6,b=1/6 a=1/6,b=5/6 a=-1/6,b=-5/6 a=-5/6,b=-1/6](/uploads/image/z/7004715-51-5.jpg?t=%E5%87%BD%E6%95%B0y%3Dtan%5B%281%2Bx%2F%28a%2Bb%29%5D%E7%9A%84%E5%91%A8%E6%9C%9F%E4%B8%BA%CF%80%2Cy%3Dsin%28%28a-b%29x%2B%CF%80%2F4%29%E7%9A%84%E5%91%A8%E6%9C%9F%E4%B8%BA3%CF%80%2C%E6%B1%82a%2Cb%E7%9A%84%E5%80%BC.%E7%AD%94%E6%A1%88a%3D5%2F6%2Cb%3D1%2F6+a%3D1%2F6%2Cb%3D5%2F6+a%3D-1%2F6%2Cb%3D-5%2F6+a%3D-5%2F6%2Cb%3D-1%2F6)
函数y=tan[(1+x/(a+b)]的周期为π,y=sin((a-b)x+π/4)的周期为3π,求a,b的值.答案a=5/6,b=1/6 a=1/6,b=5/6 a=-1/6,b=-5/6 a=-5/6,b=-1/6
函数y=tan[(1+x/(a+b)]的周期为π,y=sin((a-b)x+π/4)的周期为3π,求a,b的值.
答案a=5/6,b=1/6 a=1/6,b=5/6 a=-1/6,b=-5/6 a=-5/6,b=-1/6
函数y=tan[(1+x/(a+b)]的周期为π,y=sin((a-b)x+π/4)的周期为3π,求a,b的值.答案a=5/6,b=1/6 a=1/6,b=5/6 a=-1/6,b=-5/6 a=-5/6,b=-1/6
y=tan[(1+x/(a+b)]的周期T=π/[|1/(a+b)|]
y=sin((a-b)x+π/4)的周期T=2π/(|a-b|)
由题意,得
π/[1/(a+b)]=π
2π/(a-b)=3π
∴a+b=1
a-b=2/3
∴a=5/6
b=1/6
刚明白为什么是四种结果
第二种情况是：
π/[-1/(a+b)]=π
2π/[-(a-b)]=3π
此时,a+b=-1,b-a=2/3,
此时,a=-5/6,b=-1/6
第三种情况是:
π/[1/(a+b)]=π
2π/[-(a-b)]=3π
此时,a+b=1,b-a=2/3
∴a=1/6,b=5/6
第四种情况：
π/[-1/(a+b)]=π
2π/[(a-b)]=3π
此时a+b=-1,a-b=2/3
∴a=-1/6,b=-5/6
谢谢
由题意知：π/|a+b|=π 2π/|a-b|=3π
所以|a+b|=1 |a-b|=2/3
所以a+b=1 a-b=2/3或a+b=1 a-b=-2/3或a+b=-1 a-b=2/3 或a+b=-1 a-b=-2/3
解得：a=5/6 b=1/6 a=1/6 b=5/6 a=-1/6 b=-5/6 a=-5/6 b=1--1/6