13x^2-6xy+y^2-4x+1=0,求(x+y)^13*x^10的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/11 00:13:42
13x^2-6xy+y^2-4x+1=0,求(x+y)^13*x^10的值

13x^2-6xy+y^2-4x+1=0,求(x+y)^13*x^10的值
13x^2-6xy+y^2-4x+1=0,求(x+y)^13*x^10的值

13x^2-6xy+y^2-4x+1=0,求(x+y)^13*x^10的值
亲,原式变形为
9x^2-6xy+y^2+4x^2-4x+1=0
(3x-y)^2+(2x-1)^2=0
又因为(2x-1)^2>=0,(3x-y)^2>=0,
所以只有(2x-1)^2=0,(3x-y)^2=0,即
x=1/2
y=3/2
代入(x+y)^13*x^10=(1/2+3/2)^13*1/2^10=2^13*1/2^10=(2*1/2)^10*2^3=8

1-2/x+y=xy,4y+6x=xy.求xy的解? 已知13X^2-6XY+Y^2-4X+1=0,求(XY-X^2)^5的值. 已知13x^2-6xy+y^2-4x+1=0,求(xy-x^2)^3的值. 已知13X^2-6XY+Y^2-4x+1=0,求(x+y)^13乘以x^10 已知:13x^2-6xy+y^2-4x+1=0,求(x+y)^2013*x^2011 已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎 化简求值x-4y/2x-7xy+3y×x-2xy-3y/2x+3xy-2y÷3x-6y/4x-4xy+y,其中:x=1999,y=-1 已知x^2+y^2-4x+6y+13=0求(xy+y^2/5x^2-5xy+xy+y^2)·(5/x+y)-(y/x-y) 1.已知x+y=-4,xy=3,求5(2分之1xy+2y)+[6x-(2xy+y-3x)]的值2.已知(x+3)^2+|x-y+10|=0求代数式5x^2y-[2x^2y-(3xy-xy^2)-3x^2]-2xy^2-y^2的值 X×X-2XY-Y×Y+2X-2Y+2=02X×2X-4XY-2Y×2Y+3X-3Y+4=0X×X+2XY+Y×Y+X+Y-56=0X×X-2XY+Y×Y-X+Y-12=0X×X-3XY+Y×Y=-13X×3X-XY+3Y×3Y=13 两个在一起的方程之间有所联系(要求一步一步写出来) 4xy-[(x²+5xy-y²)-(3xy-1/2y)]x=3,y=-6 -3(2x-xy)-4(-6+xy+x.其中x=1,y=-1 已知x-y=6,xy=-1,求(2x+3x-2xy)-(x+4y+xy)-(3yx-2x+2y)的值 已知/X-Y-1/+(XY+3)的平方=0,求(-2XY+2X+3Y)-(3XY+2Y-2X)-(X+4Y+XY)的值!已知/X-Y-1/+(XY+3)的平方=0,求(-2XY+2X+3Y)-(3XY+2Y-2X)-(X+4Y+XY)的值急! 已知|X-3Y-1|+(X+Y)^=4XY,求X/Y的值另外还有道:已知X^2+Y^2+6X-4Y+13=0,①求X,Y的值②X^2-Y^2的值已知|X-3Y-1|+(X+Y)^2=4XY,求X/Y的值 已知13x^2-6xy+y^2-4x+1=0,求(x^2-xy)^5的值特别注意是求(x^2-xy)^5的值,不是(xy-x^2)^5的值 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? (1)已知x+y=6,xy=-3,x^2y+xy^2=(2)x*[2-(1/x)]+(x/x^2-2x)*(x^2-4)