作业帮设函数f(x)在[0,1]上连续,证明：∫（0->1）dx∫（0->1）dy∫（x->y）f(x)f(y)f(z)dz=0
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![设函数f(x)在[0,1]上连续,证明：∫（0->1）dx∫（0->1）dy∫（x->y）f(x)f(y)f(z)dz=0](/uploads/image/z/4058535-39-5.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%5B0%2C1%5D%E4%B8%8A%E8%BF%9E%E7%BB%AD%2C%E8%AF%81%E6%98%8E%EF%BC%9A%E2%88%AB%EF%BC%880-%3E1%EF%BC%89dx%E2%88%AB%EF%BC%880-%3E1%EF%BC%89dy%E2%88%AB%EF%BC%88x-%3Ey%EF%BC%89f%28x%29f%28y%29f%28z%29dz%3D0)
设函数f(x)在[0,1]上连续,证明：∫（0->1）dx∫（0->1）dy∫（x->y）f(x)f(y)f(z)dz=0
设函数f(x)在[0,1]上连续,证明：∫（0->1）dx∫（0->1）dy∫（x->y）f(x)f(y)f(z)dz=0
设函数f(x)在[0,1]上连续,证明：∫（0->1）dx∫（0->1）dy∫（x->y）f(x)f(y)f(z)dz=0
