作业帮当x=2,y=1 求{(x2+y2)/(x2-2xy+y2)+(2)/xy÷[(1/x)-(1/y)]}÷(x+y)的值
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/13 00:08:07
![当x=2,y=1 求{(x2+y2)/(x2-2xy+y2)+(2)/xy÷[(1/x)-(1/y)]}÷(x+y)的值](/uploads/image/z/3948206-14-6.jpg?t=%E5%BD%93x%3D2%2Cy%3D1+%E6%B1%82%7B%28x2%2By2%29%2F%28x2-2xy%2By2%29%2B%282%29%2Fxy%C3%B7%5B%281%2Fx%29-%281%2Fy%29%5D%7D%C3%B7%28x%2By%29%E7%9A%84%E5%80%BC)
当x=2,y=1 求{(x2+y2)/(x2-2xy+y2)+(2)/xy÷[(1/x)-(1/y)]}÷(x+y)的值
当x=2,y=1 求{(x2+y2)/(x2-2xy+y2)+(2)/xy÷[(1/x)-(1/y)]}÷(x+y)的值
当x=2,y=1 求{(x2+y2)/(x2-2xy+y2)+(2)/xy÷[(1/x)-(1/y)]}÷(x+y)的值
x^2+y^2=5;
x^2-2xy+y^2=1;
2/xy/[(1/x)-(1/y)]=-2;
最后得到值为1