f(x/x+2)=f(x+1)/x+3,则求f(5)的值

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f(x/x+2)=f(x+1)/x+3,则求f(5)的值

f(x/x+2)=f(x+1)/x+3,则求f(5)的值
f(x/x+2)=f(x+1)/x+3,则求f(5)的值

f(x/x+2)=f(x+1)/x+3,则求f(5)的值
当x = 4 则f(2/3) = f(5)/7
当x = -1/3 则f(-1/5) = f(2/3) / (8 / 3)
当X = -6/5 则f(-3/2) = f(-1/5)/(9/5)
当x = -5/2 则f(5) = f(-3/2)/(1/2)
则循环一遍后发现f(5) = a*f(5)(a为常数,我就不算了,就上面的相乘),也就是f(5) = 0
或者我不知道有没有理解错你题目的意思
等号右边是(f(x+1)/x)+3
是这样的话
当x = 4 则f(2/3) = f(5)/5 + 3
当x = -1/3 则f(-1/5) = f(2/3)/(-1/3) + 3
当X = -6/5 则f(-3/2) = f(-1/5)/(-6/5) + 3
当x = -5/2 则f(5) = f(-3/2)/(-5 / 2) + 3
则f(5)=-1/6