因式分解(会几道做几道）y^2+(a^2+b^2)y+a^2b^2abx^2-（ac-b^2)x-bc6x^2+31x-1053x^4-7x^2y^2-20y^46a^4n+k-a^2n+k-35a^k1\3x^3-5\3x^2-8xx(x-1)(x+1)(x+2）-24(x+1)(x+2)(x+3)(x+4)-24

来源：学生作业帮助网编辑：作业帮时间：2024/05/05 15:52:16

$因式分解(会几道做几道）y^2+(a^2+b^2)y+a^2b^2abx^2-（ac-b^2)x-bc6x^2+31x-1053x^4-7x^2y^2-20y^46a^4n+k-a^2n+k-35a^k1\3x^3-5\3x^2-8xx(x-1)(x+1)(x+2）-24(x+1)(x+2)(x+3)(x+4)-24$

因式分解(会几道做几道）y^2+(a^2+b^2)y+a^2b^2abx^2-（ac-b^2)x-bc6x^2+31x-1053x^4-7x^2y^2-20y^46a^4n+k-a^2n+k-35a^k1\3x^3-5\3x^2-8xx(x-1)(x+1)(x+2）-24(x+1)(x+2)(x+3)(x+4)-24
因式分解(会几道做几道）
y^2+(a^2+b^2)y+a^2b^2
abx^2-（ac-b^2)x-bc
6x^2+31x-105
3x^4-7x^2y^2-20y^4
6a^4n+k-a^2n+k-35a^k
1\3x^3-5\3x^2-8x
x(x-1)(x+1)(x+2）-24
(x+1)(x+2)(x+3)(x+4)-24

因式分解(会几道做几道）y^2+(a^2+b^2)y+a^2b^2abx^2-（ac-b^2)x-bc6x^2+31x-1053x^4-7x^2y^2-20y^46a^4n+k-a^2n+k-35a^k1\3x^3-5\3x^2-8xx(x-1)(x+1)(x+2）-24(x+1)(x+2)(x+3)(x+4)-24
y^2+(a^2+b^2)y+a^2b^2
=(y+a^2)(y+b^2)
1/3x(x-8)(x+3)
x(x - 1)(x + 1)(x + 2) - 24
= x(x^2 - 1)(x + 2) - 24
= x(x^3 + 2x^2 - x - 2) - 24
= x^4 + 2x^3 - x^2 - 2x - 24
= (x^4 - 2x^3) + 4x^3 - x^2 - 2x - 24
= x^3(x - 2) + 4x^3 - 8x^2 + 7x^2 - 2x - 24
= (x^3 + 4x^2)(x - 2) + (7x^2 - 14x) + (12x - 24)
= (x^3 + 4x^2 + 7x + 12)(x - 2)
= [(x^3 + 3x^2) + (x^2 + 3x) + (4x + 12)](x - 2)
= (x^2 + x + 4)(x + 3)(x - 2)
(x+1)(x+2)(x+3)(x+4)-24因式分解
原式=[(x+1)(x+4)]*[(x+2)(x+3)]-24
=(x^2+5x+4)*(x^2+5x+6)-24
设A=x^2+5x,则
原式=(A+4)(A+6)-24=A^2+10A+24-24=A^2+10A
原式=A(A+10)
=(x^2+5x)(x^2+5x+10)
=x(x+5)(x^2+5x+10)

y^2+(a^2+b^2)y+a^2b^2
=（y+a^2）（y+b^2）
abx^2-（ac-b^2)x-bc
=（ax+b）（ax-c）
6x^2+31x-105
=（2x+15）（3x-7）
3x^4-7x^2y^2-20y^4
=(x^2-4y^2)(3x^2+5y^2)
=(x+2y)(x-2y)(3x^2+5y^2)

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y^2+(a^2+b^2)y+a^2b^2
=（y+a^2）（y+b^2）
abx^2-（ac-b^2)x-bc
=（ax+b）（ax-c）
6x^2+31x-105
=（2x+15）（3x-7）
3x^4-7x^2y^2-20y^4
=(x^2-4y^2)(3x^2+5y^2)
=(x+2y)(x-2y)(3x^2+5y^2)
6a^4n+k-a^2n+k-35a^k
=[2a^(n+k)-5k][3a^(n+k)+7k]
1\3x^3-5\3x^2-8x
=(x-8)(1/3x+1)
x(x - 1)(x + 1)(x + 2) - 24
= x(x^2 - 1)(x + 2) - 24
= x(x^3 + 2x^2 - x - 2) - 24
= x^4 + 2x^3 - x^2 - 2x - 24
= (x^4 - 2x^3) + 4x^3 - x^2 - 2x - 24
= x^3(x - 2) + 4x^3 - 8x^2 + 7x^2 - 2x - 24
= (x^3 + 4x^2)(x - 2) + (7x^2 - 14x) + (12x - 24)
= (x^3 + 4x^2 + 7x + 12)(x - 2)
= [(x^3 + 3x^2) + (x^2 + 3x) + (4x + 12)](x - 2)
= (x^2 + x + 4)(x + 3)(x - 2)
(x+1)(x+2)(x+3)(x+4)-24因式分解
解:
原式=[(x+1)(x+4)]*[(x+2)(x+3)]-24
=(x^2+5x+4)*(x^2+5x+6)-24
设A=x^2+5x,则
原式=(A+4)(A+6)-24=A^2+10A+24-24=A^2+10A
原式=A(A+10)
=(x^2+5x)(x^2+5x+10)
=x(x+5)(x^2+5x+10)

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