作业帮怎样化简³√[(x-5)^2]+(x+10)*2/3*(x-5)^(-1/3)答案是5/3*(x+1)/³√(x-5)
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/30 22:48:16
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怎样化简³√[(x-5)^2]+(x+10)*2/3*(x-5)^(-1/3)答案是5/3*(x+1)/³√(x-5)
怎样化简³√[(x-5)^2]+(x+10)*2/3*(x-5)^(-1/3)
答案是5/3*(x+1)/³√(x-5)
怎样化简³√[(x-5)^2]+(x+10)*2/3*(x-5)^(-1/3)答案是5/3*(x+1)/³√(x-5)
原式*³√(x-5) = (x-5) +(x+10)*2/3 = x-5+2/3*x+20/3 = 5/3*x + 5/3 = 5/3*(x+1)
因此,原式 = 5/3*(x+1) / ³√(x-5)