在三角形ABC中,a=4,b=5/2,5cos(B+C)+3=0,则角B的大小为A.π/6 B.π/4 C.π/3 D.5π/6

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在三角形ABC中,a=4,b=5/2,5cos(B+C)+3=0,则角B的大小为A.π/6 B.π/4 C.π/3 D.5π/6

在三角形ABC中,a=4,b=5/2,5cos(B+C)+3=0,则角B的大小为A.π/6 B.π/4 C.π/3 D.5π/6
在三角形ABC中,a=4,b=5/2,5cos(B+C)+3=0,则角B的大小为
A.π/6 B.π/4 C.π/3 D.5π/6

在三角形ABC中,a=4,b=5/2,5cos(B+C)+3=0,则角B的大小为A.π/6 B.π/4 C.π/3 D.5π/6
5cos(B+C)+3=0
5cos(π-A)+3=0
-5cosA+3=0
cosA=3/5
则sinA=√[1-(3/5)²]=4/5
由正弦定理得
sinB=(4/5)(5/2)/4=1/2
∵b