作业帮1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2（2a-4b+c）+（a+3b-c）=?
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/01 06:49:17
![1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2（2a-4b+c）+（a+3b-c）=?](/uploads/image/z/14865673-49-3.jpg?t=1%2F3%5B%282a%2B3b%29%2B1%2F2a-2%2F3%286a-5b%29%5D%3D%3F1%2F2%EF%BC%882a-4b%2Bc%EF%BC%89%2B%EF%BC%88a%2B3b-c%EF%BC%89%3D%3F)
1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2（2a-4b+c）+（a+3b-c）=?
1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?
1/2（2a-4b+c）+（a+3b-c）=?
1/3[(2a+3b)+1/2a-2/3(6a-5b)]=?1/2（2a-4b+c）+（a+3b-c）=?
1)1/3[(2a+3b)+1/2a-2/3(6a-5b)]
=1/3*[2a+3b+1/2a-4a+10/3b]
=1/3*[-3/2a+19/3b]
=-1/2a+19/9b
2)1/2（2a-4b+c）+（a+3b-c）
=a-2b+1/2c+a+3b-c
=2a-b-1/2c
1/3[(2a+3b)+1/2a-2/3(6a-5b)]
=1/3(2a+3b+a/2-4a+10b/3)
=1/3(-3a/2+19b/3)
=-a/2+19b/9
1/2（2a-4b+c）+（a+3b-c）
=a-2b+c/2+a+3b-c
=2a+b-c/2