(x/x+1)^ 2+(x/x+1)-6=0怎么做

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(x/x+1)^ 2+(x/x+1)-6=0怎么做

(x/x+1)^ 2+(x/x+1)-6=0怎么做
(x/x+1)^ 2+(x/x+1)-6=0怎么做

(x/x+1)^ 2+(x/x+1)-6=0怎么做
设 y= x/x+1

y^2 + y -6 =0
(y+3)(y-2)=0
y=-3 或 y=2
x/x+1 = -3
x = -3x -3
4x=-3
x=-3/4
x/x+1=2
x = 2x +2
x=-2

换元法,令t=x/(x+1),解关于t的二元一次方程。

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