已知x²+2x+y²–6y+10＝0,求x,y的值

已知x²+2x+y²–6y+10＝0,求x,y的值
已知x²+2x+y²–6y+10＝0,求x,y的值

已知x²+2x+y²–6y+10＝0,求x,y的值

x²+2x+y²–6y+10＝0
(x^2+2x+1)+(y^2-6y+9)=0
(x+1)^2+(y-3)^2=0
得{x+1=0
y-3=0
即 x=-1, y=3

（X+1）∧2+（y-3）∧2=0

(x^2+2x+1)+(y^2-6y+9)=0
(x+1)^2+(y-3)^2=0
x+1=0
y-3=0
x=-1
y=3