若实数x,y满足x|x|+y|y|=1,则点(x,y)到直线x+y=0的距离的取值范围是

若实数x,y满足x-y+1》=0,x+y>=0,x 若实数x,y满足x-y+1>=0,x+y>=0,x 若实数x,y满足x>=1,y>=1,x+y 已知实数x,y满足y=|x-1|若x+2y 若实数x,y满足y 若实数x,y满足不等式y 若实数x,y满足不等式x-y>=-1,x+y>=1,3x-y 若实数x,y满足不等式x-y>=-1,x+y>=1,3x-y 若正实数x,y满足x+y+1/x+1/y=5,则x+y的最大值是多少 实数x,y满足{x-y+1>=0;y+1>=0;x+y+1 若实数xy满足x-y+1 若实数x,y是满足1 已知实数x,y满足x-y 已知实数X,Y满足{|x+y| 实数x,y满足:｜x+y｜ 若实数x,y满足x 若实数x,y满足x 已知实数x,y满足方程x*x+y*y-4x+1=0.求y-x的最大值