作业帮关于命题和函数.已知命题p:f(x)=ax^2-4x(a属于R)在(负无穷,2]上单调递减,命题q：任意x属于R,16x^2-16(a-1)x+1不等于0.若p且q为真命题,求a范围.我算出来是(1/2,
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![关于命题和函数.已知命题p:f(x)=ax^2-4x(a属于R)在(负无穷,2]上单调递减,命题q：任意x属于R,16x^2-16(a-1)x+1不等于0.若p且q为真命题,求a范围.我算出来是(1/2,](/uploads/image/z/11507059-19-9.jpg?t=%E5%85%B3%E4%BA%8E%E5%91%BD%E9%A2%98%E5%92%8C%E5%87%BD%E6%95%B0.%E5%B7%B2%E7%9F%A5%E5%91%BD%E9%A2%98p%3Af%28x%29%3Dax%5E2-4x%28a%E5%B1%9E%E4%BA%8ER%29%E5%9C%A8%28%E8%B4%9F%E6%97%A0%E7%A9%B7%2C2%5D%E4%B8%8A%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F%2C%E5%91%BD%E9%A2%98q%EF%BC%9A%E4%BB%BB%E6%84%8Fx%E5%B1%9E%E4%BA%8ER%2C16x%5E2-16%28a-1%29x%2B1%E4%B8%8D%E7%AD%89%E4%BA%8E0.%E8%8B%A5p%E4%B8%94q%E4%B8%BA%E7%9C%9F%E5%91%BD%E9%A2%98%2C%E6%B1%82a%E8%8C%83%E5%9B%B4.%E6%88%91%E7%AE%97%E5%87%BA%E6%9D%A5%E6%98%AF%281%2F2%2C)
关于命题和函数.已知命题p:f(x)=ax^2-4x(a属于R)在(负无穷,2]上单调递减,命题q：任意x属于R,16x^2-16(a-1)x+1不等于0.若p且q为真命题,求a范围.我算出来是(1/2,
关于命题和函数.
已知命题p:f(x)=ax^2-4x(a属于R)在(负无穷,2]上单调递减,命题q：任意x属于R,16x^2-16(a-1)x+1不等于0.若p且q为真命题,求a范围.
我算出来是(1/2,
关于命题和函数.已知命题p:f(x)=ax^2-4x(a属于R)在(负无穷,2]上单调递减,命题q：任意x属于R,16x^2-16(a-1)x+1不等于0.若p且q为真命题,求a范围.我算出来是(1/2,
（1/2,3/2）
我算的结果是这个
f(x)=ax^2-4x(a属于R)在(负无穷,2]上单调递减
求导2ax-4<=0,x<=2/a,0
16x^2-16(a-1)x+1=16[x-(a-1)/2]^2+1-(a-1)^2/4
1-(a-1)^2/4不等于0
a不等于3或-1
p且q为真命题a范围0